CS/알고리즘 풀이
[알고리즘_풀이] 카카오 예선, 카카오프렌즈 컬러링북
Selina Park
2019. 8. 27. 16:51
java, bfs로 구현한 코드
전형적인 graph응용문제였고 이에 따라 graph에 대하여 전반적으로 공부했다.
IDE용 코드
package codingTest;
import java.util.*;
class Node{
int x;
int y;
Node(int x, int y){
this.x = x;
this.y = y;
}
}
public class kakao_coloringbook {
static boolean[][] marked = null;
static int[][] pictures = null;
public static int bfs(int i, int j) {
//System.out.println(marked[i][j]);
int tmpPicture = pictures[i][j];
System.out.println(pictures[i][j] + " " + i + " " + j );
marked[i][j] = true;
Queue<Node> q = new LinkedList<>();
q.add(new Node(i, j));
int[] dx = {0, 0, 1, -1};
int[] dy = {1, -1, 0, 0};
int count = 1;
while(!q.isEmpty()){
Node out = q.poll();
for(int k=0; k<4; k++){
int x = out.x+dx[k];
int y = out.y+dy[k];
if(x>=0 && y>=0 && x<pictures.length && y<pictures[0].length){
if(!marked[x][y] && pictures[x][y] == tmpPicture && pictures[i][j] > 0){
count++;
marked[x][y] = true;
q.add(new Node(x, y));
}
}
}
}
return count;
}
public static int[] solution(int m, int n, int[][] picture) {
int numberOfArea = 0;
int maxSizeOfOneArea = 0;
marked = new boolean[m][n];
pictures = new int[m][n];
for(int i=0; i<m; i++){
for(int j=0; j<n; j++){
pictures[i][j] = picture[i][j];
}
}
List<Integer> count = new LinkedList<>();
//bfs구현
for(int i=0; i<m; i++){
for(int j=0; j<n; j++){
if(!marked[i][j] && pictures[i][j] > 0){
marked[i][j] = true;
count.add(bfs(i, j));
}
}
}
Collections.sort(count);
Collections.reverse(count);
numberOfArea = count.size();
maxSizeOfOneArea = count.get(0);
int[] answer = new int[2];
answer[0] = numberOfArea;
answer[1] = maxSizeOfOneArea;
return answer;
}
public static void main(String[] args) {
int m = 6;
int n = 4;
int[][] picture = {{1, 1, 1, 0}, {1, 2, 2, 0}, {1, 0, 0, 1}, {0, 0, 0, 1}, {0, 0, 0, 3}, {0, 0, 0, 3}};
int[] answer = solution(m, n, picture);
System.out.println(answer[0] + " " + answer[1]);
}
}
프로그래머스용 코드
import java.util.*;
class Node{
int x;
int y;
Node(int x, int y){
this.x = x;
this.y = y;
}
}
class Solution {
static boolean[][] marked = null;
static int[][] pictures = null;
public static int bfs(int i, int j) {
//System.out.println(marked[i][j]);
int tmpPicture = pictures[i][j];
System.out.println(pictures[i][j] + " " + i + " " + j );
marked[i][j] = true;
Queue<Node> q = new LinkedList<>();
q.add(new Node(i, j));
int[] dx = {0, 0, 1, -1};
int[] dy = {1, -1, 0, 0};
int count = 1;
while(!q.isEmpty()){
Node out = q.poll();
for(int k=0; k<4; k++){
int x = out.x+dx[k];
int y = out.y+dy[k];
if(x>=0 && y>=0 && x<pictures.length && y<pictures[0].length){
if(!marked[x][y] && pictures[x][y] == tmpPicture && pictures[i][j] > 0){
count++;
marked[x][y] = true;
q.add(new Node(x, y));
}
}
}
}
return count;
}
public int[] solution(int m, int n, int[][] picture) {
int numberOfArea = 0;
int maxSizeOfOneArea = 0;
marked = new boolean[m][n];
pictures = new int[m][n];
for(int i=0; i<m; i++){
for(int j=0; j<n; j++){
pictures[i][j] = picture[i][j];
}
}
List<Integer> count = new LinkedList<>();
//bfs구현
for(int i=0; i<m; i++){
for(int j=0; j<n; j++){
if(!marked[i][j] && pictures[i][j] > 0){
marked[i][j] = true;
count.add(bfs(i, j));
}
}
}
System.out.println("count : " + count);
Collections.sort(count);
Collections.reverse(count);
numberOfArea = count.size();
maxSizeOfOneArea = count.get(0);
int[] answer = new int[2];
answer[0] = numberOfArea;
answer[1] = maxSizeOfOneArea;
return answer;
}
}
https://programmers.co.kr/learn/courses/30/lessons/1829
코딩테스트 연습 - 카카오프렌즈 컬러링북 | 프로그래머스
6 4 [[1, 1, 1, 0], [1, 2, 2, 0], [1, 0, 0, 1], [0, 0, 0, 1], [0, 0, 0, 3], [0, 0, 0, 3]] [4, 5]
programmers.co.kr